I heared that a car battery delivers 12V,30A supply. but my ic specifications says that my workable limit is under 1A. what should i do? i need clear explanation and if possible with a schematic... and width of wire too which i must use..
2006-06-20 06:06:25 · 4 answers · asked by toocoolblue2000 1 in Science & Mathematics ➔ Engineering
The above answers about using a voltage regulator sound ok. Just make sure to check out the regulator's data sheet so that it can safely regulate what DC voltage you are giving it (though with this 12V case you shouldn't have a problem).
Also, when a battery is rated at 12V, 30A the battery doesn't necessarily output 30A at all times; that is just a full load rating given for safety reasons (don't want to overload the battery). The battery is a constant voltage source so you can certainly have a load that pulls much less than 30A.
Width of wire? You shouldn't be too concerned with this at these low voltages. Just use breadboard type wire (around 22 AWG I believe).
Also, one final comment from me... why use a car battery when you can use a more convenient source of DC voltage? If you want something that can conveniently power your IC's try one of those nifty AC/DC plugs that charge cell phones and the like. They are rated in various output voltages and can surely supply all the current your IC's will need. Just cut off the DC plug end and strip the wire. Boom, now you have DC voltage for your breadboard supply terminals or whatever.
2006-06-21 07:09:24 · answer #1 · answered by Ubi 5 · 0⤊ 0⤋
If the battery delivers 12V/30A, it means it can deliver a maximum of 30 amps when needed. Think about the voltage limit and not amp rating of the supply ( but the supply should not be underrated either). If the working voltage of your ICs are 12V then go ahead connect it to the battery and the wire you need is 14/36, it means a multicore wire of 14 strands of wires of 36SWG.of copper. This wire can withstand a load of 1 Amp. If your ICs rating is say 5 volt, then use a regulated supply for example the regulator IC 7805 to drop down the 12v to 5v which is very easy.
The current flowing through a circuit does not depend upon the supply amperage but the circuit's own impedence.
2006-06-20 07:12:33 · answer #2 · answered by pankaj s 2 · 0⤊ 0⤋
I am presuming your ICs require 5 volts. You could use a voltage regulator like a 7805 to drop the voltage. Don't worry about the 30A supply capability. Your circuit will draw what it needs and no more (unless there is a short somewhere). You might want to be sure and use a fuse.
2006-06-20 07:08:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Do yourself a favour and search on Google for "ohms law".
It isn't difficult and you will find it useful.
2006-06-20 08:39:22 · answer #4 · answered by dmb06851 7 · 0⤊ 0⤋