do not move, does this mean that the links on TOP of the chain are moving twice as fast as the machine moves?
2006-06-20 01:05:20 · 4 answers · asked by Bluebeard 1 in Science & Mathematics ➔ Engineering
You are correct. The tracks are powered by cogged wheels driven by the engine and work like the wheels of a car except they run along the track instead of the road bed. Look at the wheel when it is moving. The bottom point is momentarily fixed to the ground and the top point is moving straight ahead with a momentary velocity. The axel which is half way between the top and bottom is traveling at the average velocity:
Velocity (axel) = (Vtop + Vbottom)/ 2 = (Vtop + 0)/2 = 1/2 Vtop
The machine moves at the speed of the axel; proving your point.
An even better illusion is the fact that when a locomotive speeds down a track, part of it is always moving backwards (hint: the part of the wheel flanges below the top surface of the track!).
2006-06-20 05:05:51 · answer #1 · answered by Kes 7 · 2⤊ 1⤋
No, they do move. It's like saying the part of your car tire on the ground does not move.
The problem is relativity. They dont appear to move, if you are on the ground. If you are on the bulldozer the ground ones appear to move and the ones on top appear stationary, as they are always moving with you.
Sorry Kes, but you are fooled by an optical illusion. NO part of a wheel or tire moves backwards while they are rolling forwards. Try an experiment, put a chalk dot on a spare tire and roll it on your driveway, you will see that at no point does the mark ever go backwards.
The illusion is caused by part of the tire being behind the part on the ground. Some people even believe that tires come to complete stop once every revolution for the same reason.
2006-06-20 08:12:12 · answer #2 · answered by brooks163 3 · 0⤊ 0⤋
The track moves at a constant throughout its length. It is a perspective induced illusion that the bottom does not move while you are standing near the machine, whereas if you were to be in the cab of the dozer and could see the whole of the track it would appear as it is, moving in its entirety.
2006-06-20 08:24:34 · answer #3 · answered by nite92 3 · 0⤊ 0⤋
Yes, you are correct.
2006-06-20 08:07:54 · answer #4 · answered by mikey 5 · 0⤊ 0⤋