34: Solve:
8f = 32 + 4f
A.6
B.7
C.8
2006-06-15 03:40:12 · 15 answers · asked by Prince_Krona 2 in Education & Reference ➔ Home Schooling
subtract 4f from both sides so its now 4f=32 so f is 8
2006-06-15 03:43:44 · answer #1 · answered by Amishcow 3 · 0⤊ 0⤋
8
2006-06-15 10:34:54 · answer #2 · answered by Jessica S 3 · 0⤊ 0⤋
c 8
2006-06-15 06:34:31 · answer #3 · answered by Anonymous · 0⤊ 0⤋
8f = 32+ 4f (divide both sides by 8)
f = 4 + 0.5f (move the f's over, by subtracting 0.5f)
f - 0.5f = 4 (simplify)
0.5f = 4
Therefore if 1/2 f = 4, 1f = 8, f = 8.
The answer is c. Hope that helps!
(Ooh I forgot. Not necessarily a good idea to input the answers into the equation to find an answer. You need to work out how to problem solve. In life it isn't always multiple choice!)
2006-06-15 03:46:41 · answer #4 · answered by wedel 2 · 0⤊ 0⤋
8f-4f = 32
4 f = 32
f= 32/4
f=8
2006-06-15 03:44:13 · answer #5 · answered by dark_choclt 1 · 0⤊ 0⤋
you can try each equation. if F=6, 48=32+24.
F=7, 56=32+28
F=8, 64=32+32
The answer is C.8
2006-06-15 14:32:04 · answer #6 · answered by tb 1 · 0⤊ 0⤋
substitute (f) with one of the numbers :
A.6
8(6)=32+4(6) : then solve the problem
8*6=48
48=32+4(6)
4*6=24
48=32+24:incorrect so use another number to make the problem correct.
2006-06-15 03:49:06 · answer #7 · answered by Anonymous · 0⤊ 0⤋
The answer is C.8
2006-06-15 03:43:43 · answer #8 · answered by starrchick101 3 · 0⤊ 0⤋
8f = 32 + 4f
A. (8x6=48)=(32+4x6=56) so it doesn't come out
B. (8x7=56)=(32+4x7=60) so it doesn't come out either
C. (8x8=64)=(32+4x8=64) so this one comes out even
Sometimes it's just a matter of working the equation with the different answers to find the correct one.
2006-06-15 03:47:02 · answer #9 · answered by jenepher402 5 · 0⤊ 0⤋
8f - 4f = 32
4f = 32
f = 8
c.8
2006-06-15 17:29:07 · answer #10 · answered by chinababy 1 · 0⤊ 0⤋
c. 8
you move the 4f to the other side and convert it to negative which becomes 4f and then divide 4 with 32 which equals 8. or f=8. i think. :)
2006-06-15 03:47:08 · answer #11 · answered by car2x.geo 2 · 0⤊ 0⤋