3j - 13 = 11 + 2j please explain
A.18
B.24
C.26
2006-06-15 03:05:18 · 7 answers · asked by Prince_Krona 2 in Education & Reference ➔ Home Schooling
3j-2j=24 so 1j=24
2006-06-15 03:09:12 · answer #1 · answered by mi_gl_an 4 · 0⤊ 0⤋
you're trying to solve for j, so you do this:
3j-13=11+2j
(3j-2j) - 13 = 11+ (2j-2j)
(1j) - 13 = 11 + 0
j - 13 = 11
j = 11 + 13
j= 24 (answer "B")
2006-06-15 10:11:53 · answer #2 · answered by Anonymous · 0⤊ 0⤋
well...
you add 13 to both side
3j-13+13= 11+2j+13
then you sub. 2j from both sides
3j-2j=24+2j-2j
then... it's
j= 24
CHECK!!!!
3j-13=11+2j
3(24)-13=11+2(24)
72-13=11+48
59=59
the check worked so the answer is b. 24
2006-06-15 10:21:04 · answer #3 · answered by tigger 1 · 0⤊ 0⤋
j=24
2006-06-15 10:12:50 · answer #4 · answered by myaih12 1 · 0⤊ 0⤋
3j-2j=13+11
j=24
2006-06-15 12:00:49 · answer #5 · answered by Balma 2 · 0⤊ 0⤋
on both sides
+13-11-2j therefore the eqn becomes
j=24
2006-06-15 10:09:24 · answer #6 · answered by Anonymous · 0⤊ 0⤋
the answer is 24.
take 2j to the left side. so left side becomes 1j. 13 goes to the other side and becomes 24.
2006-06-15 10:33:02 · answer #7 · answered by @LpHi!i 3 · 0⤊ 0⤋