Math problem ,How to solve?

Question

I need help I am helping my daughter with her math ,however i am a little rusty . Please help with the following .

Multiply and express the product in simplest form
4 ____?___
x+2= (x+2) (x+1)

Please explain the steps you take in solving .

regards
shakespeare

Answer 1

This is the answer i got when i worked out the problem
1. You have to distribute the (x + 2) & (x + 1)....you do the by using the FOIL method....Firsts Outsides Insides Last and you get: x + 2 = x^2 + 3x + 2

2. Get rid of the 2 on the left side by subtracting it on the right side and you end up with : x = x^2 + 3x

3. Now you can move the x on the left to the right side too so you have: 0 = x^2 + 2x

4. Pull out and x leaving you with 0= x (x+2)

5. x = 0 and x = -2

My algebra is rusty but I think this is how it's done.

Answer 2

If x+2 = (x+2)(x+1), notice how x+2 is on both sides of the equation? Try renaming x+2 as something simpler like 5. So the equation would look like this......5 = 5(x+1). In order to make this true, x+1 would have to equal 1 since 5 = 5(1). Therefore x+1 = 1. If that is the case, then x must be 0 because 0+1 = 1. So the solution to the equation is x = 0.

Check: 0+2 = (0+2)(0+1) .... 2 = (2)(1) .... 2 = 2 .... True!

But, there are actually two answers!! See below.....

This is just one way to explain how to solve this problem. You can also show solving the equation by .... (note: x^2 means x squared)

x+2 = (x+2)(x+1) ....... multiply the binomials

x+2 = x^2 + x + 2x + 2 ....... add x + 2x

x+2 = x^2 + 3x + 2 ....... now take 2 away from each side

0 = x^2 + 2x ..... factor out an x from each term

0 = x(x + 2) ..... set x and x+2 each = to zero

So, x = 0 or x + 2 = 0 ... which means x = -2 or x = 0

Therefore, the solutions are x = 0 and x = -2.

Answer 3

In order to solve this problem you need to use the distribution property when dealing with equations in parenthesis. So – you have

X + 2 = (x+2)(x+1)

First step – In any math problem, you should deal with the parenthesis first. Multiply the two parenthesis out to expanded form …
So x*x = x^2 (FYI - ^ means that the 2 is an exponent – or “x squared” as you would say)

Then x*1 = x
Then 2*x = 2x
Then 2*1 = 2

So you now have your original numbers on the left and the new expanded equation on the right

X + 2 = x^2 + x + 2x + 2

Now you will combine like terms on each side. For this problem, only the right side has like terms that you can combine – the x and the 2x. So you now have

X + 2 = x^2 + 3x + 2
Now, begin to reduce this to simplest form. Remember – Whatever you do on one side, you need to do the same thing on the other side.

First, we will subtract 2 from each side.
X = x^2 + 3x

Now, subtract x from each side.

0 = x^2 + 2x

Now subtract 2x from each side

-2x = x^2

Divide each side by x
-2 = x

This is your final answer X = -2.

Hope this helps!

Answer 4

Try this:
x+2=(x+2)(x+1)

x+2=x^2+2x+x+2

x+2=x^2+3x+2

0=x^2+2x or 0=x(x+2)

I assume you don't have to solve for x? If you do, then x=0 or
x= -2

Hope that helps...

Answer 5

divide both sides of the equation by (X+2):
1 = (X+1)
subtract 1 from both sides of the equation:
0 = X
So, the only value of X that the solution to the equation can have is X = 0

Answer 6

The answer is x=0. Both sides of the equation must equal the same amount. Always follow the order of operations. Anything in parentheses is always first, then the multiplication, then the addition.

Answer 7

x+2=x^2+3X+2 (this is the equation multiplied out)
x=x^2+3X-X (subtracting two from both sides)
0=X^2+2x (subtracting x from both sides)
0=x(x+2)Answers are 0,-2 (taking x out from right side)

Answer 8

it way be

3X+5
or
X power of 4 + 5

Answer 9

Go back to school my child.