If both parents are RH postive, the child will also be RH positive. There is no chance of RH negativity unless at least 1 parent is negative.
2006-06-11 18:53:23
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answer #1
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answered by Jen 6
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If both parents are Rh(+), there is a chance of the baby being Rh(-).
Two genes determine the blood type. the (+) gene is dominant over the (-) gene. So if you get (+) from one parent, and (-) from the other, your blood type will be (+), but your genes will still be (+) and (-).
If both parents are Rh(+), they still could be carriers of the (-) gene, and in that case there is a 25% possibility of getting a child who has Rh(-) blood.
25% because all possible combinations are:
1. (+) & (+) which will cause the child to have Rh(+) blood.
2. (-) & (+) which will cause the child to have Rh(+) blood (the (+) is dominant).
3. (+) & (-) which will cause the child to have Rh(+) blood.
4. (-) & (-) which will cause the child to have Rh(-) blood.
2006-06-12 01:52:58
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answer #2
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answered by brand_new_monkey 6
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It all depends on whether the parents are homozygous A pos or heterozygous A pos. If they are pure from parents that are pure then the children will be pure. But if they are a mix of both, then there is the possibility. The punnet square only assumes that there was one parent contributing to the factor.
2006-06-12 01:58:06
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answer #3
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answered by The Y!ABut 6
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chances are zero!!Rh groupin is based on three antigens-C,D,E out of wich D antigen is most imporatant.presence of D antigen is Rh positive n absence is Rh negative.there are no heterozygous states like Dd usually,if Dd is present it is called pseudo Rh positive,but it is very rare.so chances are zero.
2006-06-12 07:33:23
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answer #4
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answered by pishku4u 2
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if both parents have +-antigen in the blood the the more possibility is +-in child
2006-06-12 01:53:36
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answer #5
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answered by mohd 2
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zero................. if both are positive RH the child will also be positive.
2006-06-12 01:52:27
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answer #6
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answered by deborah p 3
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form a punette square and all will be answered.
Edit: they can be --. Only ++ (1x), and +- (2x) and -- (1x)
2006-06-12 01:51:26
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answer #7
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answered by D 3
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all are possible
2006-06-12 03:42:42
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answer #8
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answered by Gossamer Moondancer 4
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