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hi
tanx 4 ur interest
viscocity = force/area x velocity gradient
the dimensional formulae would be M1L-1T-1
TEACH ME HOW TO DERIVE IT.
thanking u
tom

2006-06-09 19:52:29 · 3 answers · asked by remo 2 in Science & Mathematics Physics

3 answers

mass=M,length=L,time=T.force=mass *acceleration=M*L*(T^-2).
area=L^2
velocity gradient=velocity/lenth
=L(T^-1)/L=T^-1
hence the final result is obtained by mere substitution.

2006-06-09 20:09:42 · answer #1 · answered by Anonymous · 0 0

Velocity = distance/time where distance is in length so
Velocity = LT-1 ===> M0L1T-1
Simillarly Force = Mass X Acceleration
and etc so you can derive these

2006-06-10 14:11:38 · answer #2 · answered by --> ( Charles ) <-- 4 · 0 0

F = [MLT^-2]

A = [L^2]

dv/dx = [T^-1]

Now just multiply and divide

2006-06-10 03:04:07 · answer #3 · answered by ag_iitkgp 7 · 0 0

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