I know it is a random question but i am really bad at math!
2006-06-09 14:54:21 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
96 + 95 + 97 + 99 = 387
99 + 99 + 98 + 90 = 386
The first set is larger.
(Note: It is unnecessary to divide by 4 to get the average in this problem because there are the same number of terms in each set.)
2006-06-09 14:58:46 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Find average in 3 ways:
#1: Mean
Group 1: (96+95+97+99)/4 = 96.75
Group 2: (99+99+98+90)/4 = 96.5
Group 1 is larger.
#2: Median
Group 1: (96+97)/2 = 96.5
Group 2: (98+99)/2 = 98.5
Group 2 is larger.
#3: Mode
Group 1: 95,96,97,99 all appear once, so they are all mode of this group.
Group 2: 99 appears the most in the group, so 99 is the mode.
Can't tell which group is larger.
2006-06-09 16:48:25 · answer #2 · answered by Jason L 1 · 0⤊ 0⤋
1
2006-06-09 15:07:03 · answer #3 · answered by shainty 1 · 0⤊ 0⤋
The first Set
2006-06-09 15:03:20 · answer #4 · answered by trebor2 6 · 0⤊ 0⤋
6+5+7+9=11+16=27
9+9+8+0=18+8=26
the first one no mistery there
2006-06-09 15:31:28 · answer #5 · answered by Anonymous · 0⤊ 0⤋
the first set
2006-06-09 14:59:41 · answer #6 · answered by Anonymous · 0⤊ 0⤋
the first set averages out to 96.75.
next set 96.5.
2006-06-09 15:57:58 · answer #7 · answered by Jezabel the annoyed cat 7 · 0⤊ 0⤋
the first one..
its really simple..
Avg=sum of all the elements / number of elements.
2006-06-09 15:02:21 · answer #8 · answered by Akash kaul 2 · 0⤊ 0⤋
96.75 (1)
96.5 (2)
note for you: who cares
â
â
â
â
2006-06-09 14:57:53 · answer #9 · answered by ♥ The One You Love To Hate♥ 7 · 0⤊ 0⤋