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2006-06-09 14:04:54 · 6 answers · asked by goring 6 in Science & Mathematics Physics

note ;On Coulomb is the Unit of Energy(joules)of the sum of the energies of 6.2415 x10^18 electrons flowing in a cross section of conductor moving at the Speed of 4.15*10^5meters per seconds.

2006-06-09 14:22:29 · update #1

6 answers

[V]=J/C=W/A=Kg.m^2/(s^3.A)

For experimental reasons A is the base unit and not C, you can not count electrons one by one, not yet probably soon

2006-06-09 15:49:48 · answer #1 · answered by Anonymous · 0 1

I'm not sure what you're asking. What is a "dimension less Unit"?
A watt is a unit of work (power), is usually considered lost energy as heat and is defined as the voltage times the current in a circuit. Watts have nothing to do with light output but are on lamps as a convenience for comparison. There are other formulas for finding watts when two of these are known: voltage, current, resistance. It can also be converted into horsepower: 746 watts = 1 hp. Check Google or Wikipedia for Watt's Law info.

2006-06-09 21:16:22 · answer #2 · answered by da maestro 3 · 0 0

No. Volt is a unit of energy per unit charge (specifically, joules per coulomb). It represents the strength of the potential difference between two points in a circuit. Amperage is the amount of charge that flows through a circuit per second, and so V*A would give you the power - all three units have dimension.

2006-06-09 21:12:12 · answer #3 · answered by Pascal 7 · 0 0

Your definiton that

“One Coulomb is the Unit of Energy (joules) of the sum of the energies of 6.2415 x10^18 electrons flowing in a cross section of conductor moving at the Speed of 4.15*10^5meters per seconds”

is not correct.

6.2415 x10^18 electrons have a total charge of one coulomb. (coulomb is the unit of charge)

Mass, length and time are the fundamental quantities; any other quantity can be expressed in terms of these quantities.

Therefore, the charge can be expressed in term of these quantities. But to simplify things, in SI system of units, current (rate of flow of charge, Q/t) is taken as another basic quantity.

Therefore the dimension of charge is ‘Current x time’.

The dimension of power is that of energy per unit time or Force x distance /time or
mass x square of length / cube of time.

Dimension of volt is that of energy / coulomb or energy / (current x time)

Therefore dimension of Potential difference (volt) is mass x square of length / current x (time) ^ 4.

2006-06-09 23:25:42 · answer #4 · answered by Pearlsawme 7 · 0 0

Watts = Volts * Amperes = (Amperes^2) * Resistance = (Volts^2)/Resistance

They're all the same because Volts = Amps * Resistance

2006-06-09 21:55:32 · answer #5 · answered by Steve 7 · 0 0

No,watt and volt are similar terms.

2006-06-09 21:10:48 · answer #6 · answered by Anonymous · 0 0

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