A person lays out four cards on the table, each card has an alphabet on one side & a number on the other side of it. Now, he claims "if there is a vowel on one side, there is an even number on the other side". You want to test his claim, i.e. whether he is right or wrong, but he will only allow you to flip-over two cards. The four cards laid out are as follows:
A F 2 7
Which are the two cards you will flip over to test his claim?
2006-06-09 11:07:02 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
A & 7
You flip the A to make sure the other side is even.
You flip the 7 to make sure the other side isn't a vowel.
You don't care about what is on the other side of the 2 or the F since they can be anything and not contradict the statement.
2006-06-09 11:18:32 · answer #1 · answered by rt11guru 6 · 10⤊ 0⤋
Now, the first thing we have to assume is that this game is fair, meaning that you don't have 3 cards that either always fit the problem or never fit the problem, and a fourth card that is the opposite of the other 3
Then there are 2 combinations that you can test,
A 7
2 F
You can not test A 2, 7 F, A F, or 2 7, because each of these fall in the same case with each other, A 2 and 7 F are the case that you could expect the opposite side of card 1 to be card 2. You cannot test A F or 2 7 because the 2 cards are of the same type of caracter, and you don't know which 2 cards follow the rule and 2 cards don't trick the other person might use and still keep it a problem that can be solved.
2006-06-09 22:38:29 · answer #2 · answered by waysj 3 · 0⤊ 0⤋
A and 2
2006-06-09 19:58:10 · answer #3 · answered by arthurbc1 6 · 0⤊ 0⤋
Considering he makes no statement as to whether there might also be vowels on odd-numbered cards, or if there might be odd numbers on the consonant cards (ie; he does not make them mutually exclusive), the only cards you need to flip to test his claim are the A and the 2. If the A has an even number on the back, and the 2 has a vowel, you have substaniated his claim in its entirity.
Am I right?
2006-06-09 18:13:03 · answer #4 · answered by swalker5037 2 · 0⤊ 0⤋
this is an if then statement, and using Logic --not trying to be funny, its an actual field of study, you have to consider the following table
Letter number valid
vowel even yes
vowel odd no
-vowel even yes
-vowel odd yes
so, the two cards to check are A and 7, if the other side of A is even and the other side of 7 is a vowel then the statement is true, if either of those are not the case (the other side of 7 is not a vowel, or the other side of A is not even) then the statement is false, regardless of the card due to the second line in my table
hope this helps
matttlocke
2006-06-09 18:27:05 · answer #5 · answered by matttlocke 4 · 0⤊ 0⤋
A & F because the relationship involved letters to numbers. So you'd have to test if 1) the A had an even number on one side and 2) that the F didn't.
2006-06-09 18:10:52 · answer #6 · answered by dr platypus 3 · 0⤊ 0⤋
A and 7.
An "If..., then..." statement is only false if the "if" part is true and the "then" part is false.
The A card must have an even number on the other side.
The 7 card must have a consonant on the other side. If there was a vowel on the other side, then the statement would be false.
2006-06-09 18:30:30 · answer #7 · answered by MsMath 7 · 0⤊ 0⤋
I would say A and 2.
So whats the answer?
2006-06-09 18:23:50 · answer #8 · answered by Mezee 3 · 0⤊ 0⤋
f and 2 deffientally
2006-06-09 18:17:22 · answer #9 · answered by Allie Z 1 · 0⤊ 0⤋
i dont know but yo sound cute and funny so i just wanted to answer first
2006-06-09 18:10:04 · answer #10 · answered by Anonymous · 0⤊ 0⤋