2006-06-09 10:48:22 · 12 answers · asked by mary f 1 in Science & Mathematics ➔ Mathematics
-a^2+37a+102
2006-06-09 13:13:50 · answer #1 · answered by arthurbc1 6 · 0⤊ 0⤋
( a + 26 ) - ( a - 36 ) a + 76 =
a + 26 - a^2 + 36a + 76 =
-a^2 + 37a + 102
2006-06-09 21:56:53 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(a + 26) - (a - 36)a + 76
a + 26 - a^2 + 36a + 76
-a^2 + 37a + 102
2006-06-09 20:07:55 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
WE think you should do your homework yourself... you'll learn more that way... or you could ask HOW to do the problem if you're confused and want some help learning algebra. Besides, none of those answers are right!
(a+26)-(a-36)a+76=?
First you have to get rid of the pesky little 'a' that is outside the parenthasis in
(a-36)a
You do this by multiplying what is inside the parenthasis by what is outside the parenthasis. So that it looks like this.
(a-36)a (distributive prop)
[(a)a-(36)a]
a squared - 36a
(sorry couldn't find a way to get superscripts.)
That should get you far enough to figure it out on your own.
2006-06-09 17:55:00 · answer #4 · answered by Mel 2 · 0⤊ 0⤋
= (a+26)-(a-36)a+76
= (a+26)-[(a-36)a]+76
= (a+26)-(a square - 36a)+76
= (a+26)- a square - 36a + 76
= a+ 26 -a square - 36a + 76
= -a square -35a + 102
2006-06-09 18:20:31 · answer #5 · answered by Coco 4 · 0⤊ 0⤋
a+26+(-a)+36 x (-a)-76
-14 x -a
14a???
i'm not sure but this is what i think.
2006-06-09 18:28:20 · answer #6 · answered by Anonymous · 0⤊ 0⤋
a-146 or
= -(a-36)a+76
= (-a-36)a+76
= -a^2-76a-36a-112
= -a^2-112
= a+26-a^2-112
= -a-86
= -(a+86)
2006-06-09 17:52:35 · answer #7 · answered by kelly 2 · 0⤊ 0⤋
(a+26)-(a-36)a+76
a+26-a²-36a+76
-35a+102-a²
2006-06-09 17:55:34 · answer #8 · answered by tydietyler 3 · 0⤊ 0⤋
a+26-a+36+76
2a=-138
a=-138/2
a=69
2006-06-09 17:53:13 · answer #9 · answered by sparkydog_1372 6 · 0⤊ 0⤋
a=69
2006-06-09 17:58:24 · answer #10 · answered by rezu_self 2 · 0⤊ 0⤋