English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

H3C-O-H
The Electronic structure of methanol (methyl alcohol) one of the alcohols states that:

(i)There’s polarization between O and H (coz O is highly electronegative while H is electropositive) hence, the shared electrons between O and H shift towards O atom.
(ii)Now, methyl group (i.e., CH3) is electron releasing group. Coz of this the shared electrons between O n H shift towards H; hence that decreases the polarization effect.
(iii)Here, As there’s an impact on O-H bond due to methyl group why there’s not any on the non-bonding electrons of O atom ( even they are electrons and would go under the process of repulsion due to electron release by methyl group as in the case of O-H bond.)…?

Note: give some logical xplanations and mind it - it's not my homework...!

2006-06-09 06:56:54 · 3 answers · asked by Anonymous in Education & Reference Primary & Secondary Education

3 answers

i find your question, interesting but quite inexplicable .
this is something new to me . I was not very attentive in my chemistry studies ..

My memory centre is all clogged up with other facts , just now ;
this must be the reason for me , to draw a blank here

i will go hang my head in shame .

or hunt up that answer, LIT UP for all to see , on Google or some other wondrous search engine .

good luck

.

2006-06-09 07:19:35 · answer #1 · answered by sweet-cookie 6 · 1 0

um i didn't read anything u just wrote so i'm just going to say keep ur questions short pleez. this is y no one replies to them. but me :-)

2006-06-09 14:00:01 · answer #2 · answered by oXSaraXo 1 · 0 0

UHH......UMMMMM..... COULDN'T TELL YA!!!

2006-06-09 13:59:56 · answer #3 · answered by live2rock7 4 · 0 0

fedest.com, questions and answers