if i have some doubts in my physics chemistry and biology, i am unable to get them clarified. my frnds suggested to search them online. now i am doing my inter 2nd year in hyderabad, india. can any one suggest me free website for getting my doubts clarified.
2006-06-09 06:23:09 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Try calling the Just Dial talking Yellow pages of Hyderabad on 2444-4444, I am sure they would be of some good help as they have the entire hyderabad listed on their database!
Hope it helps! :)
2006-06-11 02:43:59 · answer #1 · answered by onewildnight2nite 3 · 3⤊ 0⤋
Assuming the around action is interior the vertical airplane, the sum of forces on the stone is f = MA = W +/- F, the sign reckoning on the place interior the circle the stone is. with the aid of fact the stone isn't accelerating alongside the radius R of gyration, f = SUM(radial forces) = 0 = W +/- F. meaning W = +/- F in vector format. F is the counteracting stress that makes the acceleration 0 alongside the radius. EX: while the stone is atop the circle, W = F = centrifugal - T = mv^2/R - T = mg. So the stress T = m(v^2/R - g) the place v = wR is the tangential velocity while the angular velocity is w. notice the internet stress f = W - F = 0, it particularly is 0. while the stone is on the backside, W = - centrifugal + T = - mv^2/R + T = mg so as that T = m(g + v^2/R), yet back the internet is 0.
2016-10-30 11:09:24 · answer #2 · answered by shea 4 · 0⤊ 0⤋
http://www.wikipedia.org
2006-06-09 06:26:56 · answer #3 · answered by Pascal 7 · 0⤊ 0⤋