Profit or los or nothing?????

Question

If two person sells banana at different rates, one for 2 for 5$ and other for 3 for 5$. If one peson is sick and other have to sell whole bananas, and he sell them for 5 (2+3) for 10$ (5$+5$). Will the total amount is more or less. The answer is loss always.

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Answer 1

Yeah, I believe it's loss. Even though, when one person is sick, 5 bananas are being sold for $10.00 just as previous; the rate of sale is half as previous because only one person is selling.

Answer 2

it depends . . .

Say that there are x people who buy 2 bananas for $5 and y people who buy 3 bananas for $5. Then the total profit would be 5x+5y dollars for 2x+3y bananas. Thus the average cost of each banana is 5(x+y)/(2x+3y) dollars.

Now assume that the same people buy the new choice of bananas. Thus there will be 5(x+y) bananas sold for 10(x+y) dollars. Thus the average cost for banana would be 10(x+y)/[5(x+y)]=2 dollars.

When x>y>=0, then x+(4x+5y)=5(x+y)>y+(4x+5y)=2(2x+3y). Therefore 5(x+y)/(2x+3y)>2. Thus they make more money.

When y>x>=0, then 5(x+y)<2(2x+3y). Thus 5(x+y)/(2x+3y)<2, and they make less money.

When x=y>0, then 5(x+y)=10x, and 2x+3y=5x. Therefore 5(x+y)/(2x+3y)=10x/5x=2, so they make the same amount of money.

So, to reiterate (assuming the same people buy the bananas:

By average:

They will make more money if there were more people who bought the 3 bananas for $5, than there were people who only bought 2 originally.

The will make less money if there were less people who bought the 3 bananas than the 2 bananas originally.

And they will make the same money if the same number of people bought 2 bananas and 3 bananas originally.
I hope that explains it.


To the guy who stated "it doesn't depend on anything":

Your assumption in the beginning was that the two people sold the same number of bananas. Thus the person who sold the bananas at 2 for $5 sold to more people than the person who sold the bananas for 3 for $5. Therefore you are dealing with case x>y.

Logically nobody would buy bananas from someone at a rate of 2 for $5, when there is someone selling them (maybe across the street or something) for 3 for $5. So in most cases y>x and it would be smarter to sell them for more. But then this would require someone to take into account a whole supply and demand principle, where you won't necessarily sell the same number of bananas if you raise the price. So it actually all depends on what the economics of the situation states. I eliminated the economics issue by assuming (most likely incorrectly in a real world problem) that the same number of people will by bananas.

Answer 3

first of all i should start answering this question by CLARIFYING THE QUESTION

there are two stalls that sell bananas. and each stall has the SAME AMOUNT OF BANANAS (lets say 30 each stall, for a total of 60 bananas)

first one sells 2 bananas for $5
second one sells 3 bananas for $5

first one gets sick and hands over all the bananas to the other stall (lets say who is a friend), and asks for his share of revenue back at the end of the day.

if the guy sells 5 bananas for 10 dollars (dont forget, now he has 60 bananas, 30 his own, and 30 that came from the other stall) then he would be making a mistake as to the sale price

(2 for 5) + (3 for 5) DOES NOT EQUAL TO (5 for 10)
or
stall 1: 30 bananas at a price of 2 for $5 yields = $75 revenue
stall 2: 30 bananas at a price of 3 for $5 yields = $50 revenue
if combined: 60 bananas at a price of 5 for $10 yields $ 120 revenue
hence 75 + 50 < 120

to simply demonstrate where this discrepancy is coming from, we should look at the UNIT PRICES of each offer

1st offer (2 for 5) the unit price is $2.50
2nd offer (3 for 5) the unit price is $1.66666666...
i you add those two together then 2 bananas will be worth $4.166666....
so the third offer should be:
1 banana for $2.083333... (which is $4.1666.. divided by two)

vicariously the third offer (the combined one) should be

5 bananas for $10.416666... not 5 for 10

for those people who dont see where that 41.67 cents are coming from, its because of the mistake in adding FRACTIONS

simply:

the guy who took over the other stall is trying to balance the following equation, which will never happen

5/2 + 5/3 ≠ 10/5

so the answer DOESN'T DEPEND on anything, it just doesnt follow logic.

note:
the correct formula should be something like the following (if trying to figure out the unit price)

(5/2 + 5/3)/2 (for one banana)
mutiply the whole thing by 5, you get the price of 5 bananas
so instead of 5 for 10
you should say 5 for [5/2 * (5/2 +5/3)]

Answer 4

The total amount of bananas sold is the same, and the total income is the same, so there is no loss.
Perhaps if you would proofread your question I could understand better exactly what you are asking.

Answer 5

buy them at $1.67 each and you have a profit of 33 cents if you sell at $2.00
if you buy them at $2.50 and sell at $2.00, then you have a loss of 50 cents for ea. banana