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6 answers

Here is how:

6+6+3
6+5+4
5+5+5

now change the first two around until you have all the possiblities.

2006-06-09 03:37:41 · answer #1 · answered by Eulercrosser 4 · 0 0

6+6+3
6+5+4
5+5+5

2006-06-09 10:38:35 · answer #2 · answered by lexie 6 · 0 0

There are 3 ways - 3,6,6; 4,5,6; 5,5,5. The odds are 10 in 216 that a throw of 3 dice will give you 15.

2006-06-09 10:38:05 · answer #3 · answered by TheOnlyBeldin 7 · 0 0

this is a mathamatical question, i suppose your asking about odds...since each dice has 6 sides, the numbers needed are 5, 5, 5 (or) 6, 6, 3 (or) 6,5,4 ...it would take a long time but its not impossible to happen since you have three routes to get there..if you threw the 3 dices i calculat the odds at getting either set at 216:1, but since you have 3 routes it would shorten the odds to 72:1

2006-06-09 10:52:36 · answer #4 · answered by ka5flm 2 · 0 0

there are ten possibilities


dice1 dice2 dice3

5 , 5 , 5

6 , 4 , 5

4 , 6 , 5

5 , 4 , 6

4 , 5 , 6

6 , 5 , 4

5 , 6 , 4

6 , 3 , 6

3 , 6 , 6

2006-06-09 13:10:01 · answer #5 · answered by sreeraj a 1 · 0 0

roll them yourself and find out

2006-06-09 11:29:56 · answer #6 · answered by gari 3 · 0 0

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