Here is how:
6+6+3
6+5+4
5+5+5
now change the first two around until you have all the possiblities.
2006-06-09 03:37:41
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answer #1
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answered by Eulercrosser 4
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6+6+3
6+5+4
5+5+5
2006-06-09 10:38:35
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answer #2
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answered by lexie 6
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There are 3 ways - 3,6,6; 4,5,6; 5,5,5. The odds are 10 in 216 that a throw of 3 dice will give you 15.
2006-06-09 10:38:05
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answer #3
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answered by TheOnlyBeldin 7
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this is a mathamatical question, i suppose your asking about odds...since each dice has 6 sides, the numbers needed are 5, 5, 5 (or) 6, 6, 3 (or) 6,5,4 ...it would take a long time but its not impossible to happen since you have three routes to get there..if you threw the 3 dices i calculat the odds at getting either set at 216:1, but since you have 3 routes it would shorten the odds to 72:1
2006-06-09 10:52:36
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answer #4
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answered by ka5flm 2
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there are ten possibilities
dice1 dice2 dice3
5 , 5 , 5
6 , 4 , 5
4 , 6 , 5
5 , 4 , 6
4 , 5 , 6
6 , 5 , 4
5 , 6 , 4
6 , 3 , 6
3 , 6 , 6
2006-06-09 13:10:01
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answer #5
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answered by sreeraj a 1
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roll them yourself and find out
2006-06-09 11:29:56
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answer #6
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answered by gari 3
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