How to build a regulated power supply with 1 A and without an IC?

Question

Pls include the pcb diagram and the schematic diagram

Answer 1

you would have to use a zener diode.a zener regulates voltage when in series with a resistance.your circuit should go:battery-(in series with)-resistance(xohm)-(in series with) zener-back to battery.(drawing it will help,sorry i don't know how to include diagrams in this).you then connect your appliance in parellel with the zener.[important:the zener must be connected in reverse bias,i.e the side with the black line goes eventually to "+ve" of battery]
under rev. bias the resistance of the zener goes through the roof,and it maintains a constant voltage across its terminals.which means that voltage of zener=that of appliance in parallel but current through zener =0.all the current goes through parallel appliance(since res. of zener approaches infinity).
heres how to now get 1 amp in your appliance:

1.lets say u use a 9v battery and 5 volt zener(both arbitrarily chosen and can be varied).the voltage across your parallel connection of zener and appliance will under no circumstances be compramised below 5v(zener value).
2.which means that the value of voltage across resistance in series to zener(for now unknown=(ser.r)ohms) will be[5-battery]=4volts.
4.it is obvious that only the current that flows through resistance will flow through the appliance, as it(the appliance) is in parallel with an infinite resistance zener.[path of least resistance is chosen]
5.if we need 1 amp. in appliance we need 1 amp in (ser.r)-[the resistor] which has 4 volts across it.hence the value of (ser.res) must be =4ohm.ohms law implies then that current = 1 amp.you can switch the values about according to availability of components.

Answer 2

This site may help you:
http://www.intio.or.jp/jf10zl/reg.htm