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2006-06-05 20:47:02 · 12 answers · asked by down4girlzs 1 in Sports Boxing

12 answers

Oscar de la Hoya.

2006-06-05 20:52:17 · answer #1 · answered by jess 2 · 1 0

the best pound for pound boxer of today is floyd mayweather jr. He has the speed skill and if he went back to his normal weight he has power. The best of all time would be the one and only "Sugar" Ray Robinson. All of the flash and skill that boxers show today come from him. They just dont have his substance. The man fought over 200 pro fights and won more than 90% of them. Even Muhammad Ali admits that he stole most of his moves from Ray. Who else u know(besides Roy Jones Jr. in his prime) that can hit you with 3 straight left hooks faster than most fighters can throw one jab?

2006-06-11 14:08:46 · answer #2 · answered by phillyzphinestaz 2 · 0 0

Diego Corrales way better then the people in his weight class

2006-06-10 12:29:40 · answer #3 · answered by giant 2 · 0 0

Floyd Mayweather Jr. for sure. he's the best and he's never lost. cant wait to see him an oscar de la hoya fight. it will be incredible

2006-06-06 10:50:32 · answer #4 · answered by born to live, bred to die 3 · 0 0

Please be cool and don't ask for the sam ething over and over again, here an advice look for your question on yahoo before asking it if it is there just read the answers instead of asking again and again and again ...

2006-06-06 17:58:43 · answer #5 · answered by dajukbox 3 · 0 0

Floyd. I would would say Zab Judah but he has no heart. Zab is a very skilled bum.

2006-06-06 18:29:22 · answer #6 · answered by speedlump2 3 · 0 0

oscar? hell naw

any real boxing fan will tell you it's PRETTY BOY FLOYD MAYWEATHER..

manny pacquiao comes in a close 2nd

(b-hop is gonna whoop on tarver)

2006-06-06 03:53:59 · answer #7 · answered by do it movin' 1 · 0 0

early mike tyson

2006-06-06 05:58:27 · answer #8 · answered by nikgy71 5 · 0 0

Roy Jones Jr.!!!!!!!

2006-06-11 21:35:58 · answer #9 · answered by Sister 4 · 0 0

manny pacman pacquiao

2006-06-07 01:06:52 · answer #10 · answered by Innocent C 2 · 0 0

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