What is the slope for [-2,2] and [0,2]? these are points from a perpendicular line.?

Question

The slope is supposed to be the recipricol of the original slope, i have an answer but i am still confused..this is what i got


y2 - y1 = -2 -2 =-4 = -2
--------- ------ --- ---
x2-x1 = 0+2 = 2 = 1


is -2 the answer or the RECIPROCAl 2?

i meant the points are

-2, 2

and

0,-2

Answer 1

Since you meant [-2,2] and [0,-2] as your points, then you get

-2+2/0+2 = -4/2 = -2

The slope of the actual line would be 1/2
Perpendicular means reciprocal and opposite sign
e.g.: -2 = 1/2
e.g.: 5 = -1/5
e.g.: 1/3 = -3

Answer 2

you need minus one over the original gradient (slope) for the gradient of the perpendicular line

Answer 3

i think they are ,and no the resiprical of 2 is 1/2

Answer 4

sorry, y2 -- y1 = 2 -- 2 = 0 and reciprocal will be infinite.

Answer 5

(2-2)/(0--2) = 0/2
Slope = 0, so the line is horizontal.