what is 9+3√6 /√3? the √ is square root and / is divide. i got 3+3√2?

Answer 1

I assume you mean (9+3√6) / √3

First, rationalize the denominator by multiplying the numerator and denominator by √3:
(9√3+3√18) / 3

Now you can simplify:
3√3 + √18 = 3√3 + 3√2

Answer 2

9+3rt(6) /rt(3)
rt(3){9+3rt(6)}/rt3(rt(3)
rt(3){9+3rt(6)}/3
(3)rt(3){3+rt(6)}/3
rt(3){3+rt(6)}
rt(3){3+rt(3)rt(2)}
3rt(3)+3rt(2)
3{rt(3)+rt(2)}

Answer 3

How did you get the 3? Is it 9+(3√6 /√3), or (9+3√6) /√3.
If its the former, then you'd get:
9 + 3/√3 * √6 = 9 + √3*√6 = 9 +√(18) = 9 + √(2*9) = 9 + √9*√2 = 9 + 3√2

If its the latter, then you'd get:
(√3)^4/√3 + 3√2 = (√3)^3 + 3√2 = √9*√3 + 3√2 = 3√3 + 3√2 =
3(√3 + √2).

Answer 4

I take it you want to rationalise it?
9+3√6 /√3
3(3 + √2.√3)/√3
Multiply top and bottom by √3
3√3(3+ √2.√3)/3 [ 3 top & bottom cancel]
3√3+ √2.√3.√3 = 3√3+ 3√2

Answer 5

assume it's (9 + 3√6) / √3
multiply top and bottom by √3 to get the radical out of the denominator

(9 + 3√6) / √3 = (9 √3 + 3√6 √3) / 3 =
3√3 +√18 = 3√3 + 3√2

Answer 6

The way you have written the question the 9 is not part of the numerator that is divided by the square root of 3.

If you have correctly represented the question, then the answer is : 9+3 sqrt(2)

Answer 7

12times3 divided by 1.5.....
try that on the calclator

soo...
24 -i think
im not that sure cuz i havent learned this yet

Answer 8

(9 + 3√6)/ √3 multiply by √3 to rationalise it which gives you:

= (9√3 + 3√18)/3
= 3√3 + √18
= 3√3 + 3√2
= 3(√3+√2)

Answer 9

Your answer is correct but if you actually did the square root of 2 then it will be a repeating decimal. You should leave it that way if you are allowed to keep it simple.

Answer 10

(9+3√6 ) / √3
= (9+3√6 ) √3 / 3
= 3 √3 + √18
= 3 √3 + 3 √2
= 3 ( √3 + √2 )