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find the solution set in a+bi form: x^2 +6x +12 =0
you dont have to show the work because i have the answer i just wanna check it.., thanks -D

2007-12-31 10:06:07 · 3 answers · asked by luhb u much!! 4 in Science & Mathematics Mathematics

3 answers

-3±i√3

As you requested, no work is shown.

2007-12-31 10:18:13 · answer #1 · answered by Pascal 7 · 0 0

{ -3 - i sqrt(3) , -3 + i sqrt(3) }

2007-12-31 16:52:23 · answer #2 · answered by Anonymous · 0 0

x^2 +6x +12 =0

Discriminant = (6)^2 -4(12)(1) = 36 - 48= -12 = 12i^2

x1 = (-6 + i sqrt(12))/2 = -3 + i sqrt(3)
x2 = (-6 - i sqrt(12))/2 = -3 - i sqrt(3)

Solution set =
{ -3 - i sqrt(3) , -3 + i sqrt(3) }

2007-12-31 10:17:50 · answer #3 · answered by Anonymous · 0 0

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