A child on a freely rotating merry-go-round moves from near the center to the edge. Will the rotational velocity of the merry-go-round increase, decrease, or not change at all?
PICK ONE:
The rotational velocity must decrease to conserve angular momentum because the rotational inertia of the merry-go-round will be greater with the child near the edge.
The rotational velocity must increase to conserve angular momentum because the rotational inertia of the merry-go-round will be less with the child near the edge.
The rotational velocity will not change because there is no change in the mass or the angular momentum of the merry-go-round.
2007-12-31 09:55:32 · 2 answers · asked by shamsan_415 1 in Science & Mathematics ➔ Physics
The rotational velocity must decrease to conserve angular momentum because the rotational inertia of the merry-go-round will be greater with the child near the edge.
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2007-12-31 09:58:17 · answer #1 · answered by odu83 7 · 0⤊ 0⤋
think of a spinning skater who pulls their palms inward {reducing I} and as a consequence spins quicker. by potential of this comparable concept of adjusting 2d of inertia = I: whilst a baby strikes outward on the merry-pass-around, the device will develop I, and so the merry-pass-around could lose angular velocity = w to maintain angular momentum = Iw consistent.
2016-11-27 01:31:08 · answer #2 · answered by ? 4 · 0⤊ 0⤋