1-radical 7, 1+radical 7 what is the quadratic equation explain please?

Answer 1

[ x - (1 - √7) ] [ x - (1 + √7) ] = 0
x² - (1 + √7) x - (1 - √7)x + (1 - √7)(1 + √7) = 0
x² - 2x - 6 = 0

Answer 2

a) Find the sum of the roots: 1+sqrt(7) + 1 - sqrt(7) = 2

b) Find the product of the roots: (1+sqrt(7))(1 - sqrt(7)) =
1 - 7 = -6

c) Now use the formula: x^2 -Sx + P = 0, where S is the sum of the roots and P is the product of the roots.

Then x^2 - 2x - 6 = 0

Answer 3

equation is
x^2 -- {(1--√7)+(1+√7)}x + (1--√7)(1+√7) = 0
Or x^2 -- 2x -- 6 = 0