If [OH^-]=1x10^-4M, what is the pH of the solution?

1 ⤊

2007-12-31 09:32:15 · 4 answers · asked by who? 1 in Science & Mathematics ➔ Chemistry

[OH^-]=1x10^-4M

pOH= -log([OH-])
pOH= -log(1*10^-4)
pOH= 4

pOH + pH = 14
14 - pOH = pH
14 - (4) = 10 = pH

[Answer: pH= 10]

2007-12-31 09:52:14 · answer #1 · answered by ¿ /\/ 馬 ? 7 · 0⤊ 0⤋

2007-12-31 10:21:43 · answer #2 · answered by Peter G 3 · 0⤊ 1⤋

10.0

2007-12-31 09:39:25 · answer #3 · answered by Anonymous · 0⤊ 1⤋

10.0

2007-12-31 09:36:10 · answer #4 · answered by ChemTeam 7 · 1⤊ 1⤋