Algebra help!! find zeros of a function?

Question

find all real zeros of g(x)=2x^3-x^2-10x+5

Answer 1

factor. group the 2x^3 and x^2 together and then the 10x+5.

factor out an x^2 from the first 2 factors and then factor out a -5 from the next two.

so u would have: x^2(2x-1)-5(2x-1).

the factors in parentheses MUST match!! otherwise u made a mistake. then u just group them together.

(x^2-5)(2x-1)

then just equate both factors to 0.
x= +/- sqrt of 5, 1/2

hope this helps.

Answer 2

2x^3-x^2-10x+5 = 2 x ( x^2-5) - (x^2 -5)
= (2x -1) (x^2 -5)

So the roots are 1/2, Sqrt(5), and - Sqrt(5).

Answer 3

=x^2(2x-1) - 5(2x-1)
=(x^2-5)(2x-1)
So x = +/- sqrt(5) and 1/2

Answer 4

put it on a graphing calculator, and find where x=0 that is your answer.