help please but quickly?

Question

in certain town 45% of the people have black hair , 30%nhave brown eyes and 20% have both black hair and brown eyes . if a person is selected at random from the town, the probability that he has brown eyes and doesn't have black hair is
1- 0.25
2- 0.1
3- 0.2
4- 0.3

Answer 1

The answer is 2) 0.1

If you selected a person at random you have a probability
of 30% that he has brown eyes. And this person has
10/30 chances not to have black hair. So the probability
that the person has brown eyes but bot black hair is

0.3 * 10/30 = 0.1

Answer 2

well i'm not so sure on the answer here. it really depends which way you look at it because its some what of a trick question.

either 65% of the people have black hair (45% + 20%) and 50 percent have brown eyes (30% + 20%)

or that the 20% that have both doesn't affect anything because they have already told you that 45% of the people have black hair 30 percent have brown eyes.
so its yours to choose

Answer 3

The answer is 2)0.1

This is so because in the question it stated that 30% of the people have brown eyes, and 20% have BOTH black hair and brown eyes. From this we can conclude that the 20% of the people that have Both black hair and brown eyes is part of the 30% that have brown eyes. Therefore,

30%-20%=10%, which is 0.1

Answer 4

P(NotBlack/Brown) = P(NotBlack) x P(Brown) = 0.55 x 0.30

P(NotBlack/Brown) = 0.165

Answer 5

Its 10%

Answer 6

100 people
45 have black hair
30 have brown eyes
20 have both
subtract the number of people who have both traits from just the people who have brown eyes to get the people who have brown eyes, but don't have black hair
30-20=10...10 of 100 is 0.1

2-0.1

Answer 7

Trying to answer homework question? Huh!

Answer 8

2- 0.1