A baseball player hits a fly ball that is caught about 4 seconds later by an outfielder. The path of the ball is a parabola. The ball is at its highest point as it passes teh second baseman, who is 127 feet from home plate. About how far from home plate is the outfielder at the moment he catches the ball? Explain your reasoning.
Thank you very much =]
2007-12-31 08:50:30 · 5 answers · asked by aliciaff2006 1 in Education & Reference ➔ Homework Help
I would say that the outfielder is about 254 feet from home plate because the second baser (127 feet) is when the ball reaches its peak. A ball usually reaches its peak in the middle of its flight. HOPE THAT HELPSSS
2007-12-31 08:53:59 · answer #1 · answered by mcvcm92 5 · 0⤊ 0⤋
The highest point of a parabola can be used to split the distance in half. . At its highest point (half way) the ball passed the second baseman 127 feet from home plate. The ball will travel the same distance after reaching its highest point as it did before, 127 feet. 127ft +127ft = 254ft. Tis is an approximate distance because the questions uses the term "about".
2007-12-31 09:00:48 · answer #2 · answered by scottdiesel1 2 · 0⤊ 0⤋
draw a graph. put the time (seconds) up to 5 on the x-axis and distance (feet) on the y-axis. The vertex of the parabola will be at 2, 127 because the vertex is right in the middle of the time, therefore 4/2 = 2 and at the highest point, 127 feet. Since the vertex is at the half way point, how can you find the rest of the distance...?
___ * 2 = total distance
2007-12-31 08:57:01 · answer #3 · answered by Phenix 2 · 0⤊ 0⤋
There must be a formula for this. Is there anything in your textbook that looks like a formula that would apply? I disagree with the first answer. I think that the ball will drop more rapidly as it slows down, so its flight path won't be like a semicircle.
2007-12-31 08:56:47 · answer #4 · answered by hottotrot1_usa 7 · 0⤊ 0⤋
I'm in Algebra now, and I hate it. But Good luck
2007-12-31 08:54:17 · answer #5 · answered by kayla p 1 · 0⤊ 0⤋