HELP WiiTH CHEMiiSTRY?

Question

Given the redox reaction:

2+ 3+
2Cr(s) + 3Cu (aq) --> 2Cr (aq) + 3Cu(s)

Which reaction occurs at the cathode in an electrochemical cell?

a- reduction of Cu(s)
2+
b- reduction of Cu (aq)
c- oxidation of Cr(s)
3+
d- oxidation of Cr (aq)

thanks in advance =)

sorry about the charges...ill put them directly next to the elements this time, rather than above them

2Cr(s) + 3Cu2+(aq) --> 2Cr3+(aq) + 3Cu(s)

a- reduction of Cu(s)
b- reduction of Cu2+(aq)
c- oxidation of Cr(s)
d- oxidation of Cr3+(aq)

Answer 1

2Cr(s) + 3Cu2+(aq) --> 2Cr3+(aq) + 3Cu(s)

So your 2 half reactions are:
Cr --> Cr3+ + 3e-
Cu2+ (aq) + 2e- --> Cu(s)

At the cathode, reduction is happening, so we use the 2nd half reaction. Thus to answer the question, we see that it is the reduction of Cu2+ that is reacting at the cathode end.

[Answer: A]

Answer 2

Since Cr has less electrode potential so it will be oxidised and Cu will be reduced
oxidation always takes place at anode and reduction at cathode
your charges are mixed up so i am telling u only actual situation so that u can solve it yourself
here (B)is correct answer