HELP WiiTH CHEMiiSTRY?

Question

The equation below represents the reaction for a lead-acid battery.
discharge>>
Pb + PbO2 + 2H2SO4 <----------> 2PbSO4 + 2H2O
< Which species is oxidized during the discharge of the battery?

a- PbSO4
b- H2SO4
c- PbO2
d- Pb

thanks in advance =)

Answer 1

d. Pb ; Oxidised from '0' to '2'.
NB The Pb in PbO2 is reduced from '4' to '2'

Answer 2

The anode is made of porous lead (Pb) and
the cathode is made of compressed lead oxide (PbO2). The electrodes are arranged in an alternating array, hanging in a bath of sulfuric acid (H2SO4) and separated by thin fiberglass sheets. The anode reaction: Pb(s) + SO4(2-) (aq) -) PbSO4(s) +2e- . The cathode reaction is PbO2(s) + 4H+(aq) + SO4(aq) + 2 e- -) PbSO4(s) + 2H2O(l).

Oxidation describes the loss of electrons by a molecule, atom or ion
Reduction describes the gain of electrons by a molecule, atom or ion