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In a population of rabbits, white fur is caused by the recessive allele g, and the dominant gray by G. If 36% of the population express the homozygous recessive white condition, what is the frequency of the dominant allele, G, in that population?

A. .64

B..06

C..60

D. .04

E. .40

2007-12-31 04:54:39 · 2 answers · asked by Anonymous in Science & Mathematics Biology

2 answers

This is a Hardy-Weinberg problem: p^2 + 2pq + q^2 = 1

In your problem white is recessive. 36% or 0.36 white rabbits -- q^2 = 0.36. This means that q = 0.6

We also know that the percentage of dominant alleles plus the percentage of recessive alleles must equal 100%, or p + q = 1.

p + q = 1
p + 0.6 = 1
p = 0.4 and that's the frequency of the dominnt allele.
Answer is E.

2007-12-31 06:42:56 · answer #1 · answered by ecolink 7 · 0 0

A: .64 or 64% because out of 100 rabbits 36 are white and the other 64 are gray.

2007-12-31 13:05:31 · answer #2 · answered by Deleted one 3 · 0 0

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