Culd someone help me please? thanks.
2007-12-30 20:59:04 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
f (x) = 3 sin 2(x + π/2)
Amplitude = 3
Period = π
Phase shift = - π / 2
2007-12-30 21:12:10 · answer #1 · answered by Como 7 · 3⤊ 1⤋
amplitude =3
phase shift =-pi/2
period=pi
2007-12-30 22:18:38 · answer #2 · answered by someone else 7 · 0⤊ 2⤋
The general formula:
Asin(Bx - k) +h
- k is the left or right shifts
- h is the vertical shift
A = amplitude
B = 2pi/period
period = 2pi/B
3 is the amplitude
period = 2pi/2 = pi
left shift = 1 pi
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2007-12-30 21:11:01 · answer #3 · answered by romantic 3 · 0⤊ 2⤋
Write is as
F(x) = Asin((w)x+k)
F(x) = 2sin(2x+π)
A is amplitude .
w = angular frequency .
Amplitude = 3
Phase shift = π
(w) = 2
2π/T=2
2π=2T
T=π
Period = π
2007-12-30 21:10:27 · answer #4 · answered by Murtaza 6 · 0⤊ 1⤋
the amplitude is factor by which the sine curve is 'stretched' along the y-axis.it is the maximum value the fuction attains.
it is 1 for a normal sine curve. it is the quantity which is multiplied to the sine function.
here, we see that the sine curve is stretched vertically
by a factor of 3. therefore, the amplitude of the function is 3.
the period is the factor by which the sine curve is stretched horizontally along the x-axis. it is the distance along
the x-axis between repeating y-values. it is 2*pi
for a normal sine curve. here, the curve is compressed horizontally by a factor of 2 [as can be seen in '2x']. so, the period of the fuction is 1/2 * 2pi = pi.
the phase shift is the factor by which the fuction is shifted back or forth along the x-axis. it is the quantity which is added to the variable quantity. here the phase shift is pi.
2007-12-30 21:23:58 · answer #5 · answered by Bhaskar 4 · 1⤊ 3⤋
This Site Might Help You.
RE:
Amplitude, period and phase shift for the function of f(x)= 3sin(2x + pi)?
Culd someone help me please? thanks.
2015-08-12 00:48:21 · answer #6 · answered by Errick 1 · 0⤊ 0⤋