Calculate the molecular mass of 20.9 g of sucrose in a 60.0 g of benzene and a m=5.19.?

Answer 1

molality = moles solute / Kg solvent
60.0 g = 0.0600 Kg
5.19 = moles / 0.0600
moles = 5.19 x 0.0600 = 0.311
20.9 g / 0.311 = 67.1 g/mol
Since molar mass of sucrose is 342.3 g/mol and the work is goos I thing that the data are not correct

Answer 2

Something isn't correct. Sucrose, which is hydrogen bonded, doesn't dissolve in benzene.