How many sec. will the ball be going up?
gravity =-32ft/sec.sq
2007-12-30 16:56:53 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
v = u + at
t = (v - u)/a
v = 0
u = 56
a = -32
t = (0-56)/(-32) = 1.75s
The ball will be going up for 1.75s (ignoring air resistance).
2007-12-30 17:03:51 · answer #1 · answered by gudspeling 7 · 2⤊ 0⤋
the equation of velocity is
v(t) = v_0 - gt,
where v_0 = 56 the initial velocity , the gravity acceleration is g=32
So the ball stops in the air when v = 0
Find the t from v(t) = 0.
2007-12-30 17:04:29 · answer #2 · answered by Theta40 7 · 0⤊ 0⤋
v = u - g t
0 = 56 - 32 t
t = 56 / 32 s
t = 1.75 s
2007-12-30 19:45:18 · answer #3 · answered by Como 7 · 0⤊ 0⤋
Please be careful with your units. The ball's velocity is in feet per second. Acceleration is in feet per second squared.
2007-12-30 17:20:08 · answer #4 · answered by laurahal42 6 · 2⤊ 0⤋