Solve the system by addition. 3x + y = 6 3x – y = 0
2007-12-30 15:24:35 · 5 answers · asked by cutter1890 1 in Science & Mathematics ➔ Mathematics
3x+y=6
3x-y=0
-----------
6x+0=6
6x=6
x=1
3x+y=6
3(1)+y=6
3+y=6
y=3
(1,3)
2007-12-30 15:30:25 · answer #1 · answered by Lady Lefty 3 · 1⤊ 0⤋
x = 1, y = 3
2007-12-30 23:29:07 · answer #2 · answered by David G 6 · 0⤊ 0⤋
3x + y = 6 ..... (1)
3x - y = 0 ..... (2)
----------------------------- (Adding both equations to eliminate y)
6x = 6
-> x = 1
Put x = 1 in (2),
3 - y = 0
-> y = 3
x = 1, y = 3 is the solution
2007-12-31 00:10:33 · answer #3 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
6x = 6
x = 1
3 + y = 6
y = 3
x = 1 , y = 3
2007-12-31 08:54:30 · answer #4 · answered by Como 7 · 0⤊ 0⤋
3x+y=6
3x-y=0
6x=6
x=1
subst. x into 3x+y=6,
y=3
2007-12-30 23:36:49 · answer #5 · answered by curiosium 1 · 0⤊ 0⤋