factor the trinomial.?

Question

(9x + 8)(9x + 3)

Answer 1

To expand, use the FOIL-ing method (multiplying first, outside, inside, last terms):
=(9x + 8)(9x + 3)
=81x² + 27x + 72x + 24
=81x² + 99x + 24

If you wish to factor it, "take out" a 3 from the 2nd bracket and that's your answer, so
=3(9x+8)(x+1)

Answer 2

I think it's already factored unless I'm missing something here...

You can make it like...

(9x + 8)(3)(3x + 1)

Or if you're talking about expanding it..

(9x + 8)(9x + 3)
= 81x^2 + 27x + 72x + 24
= 81x^2 + 99x + 24

Answer 3

The trinomial is already factored. If your talking about multiply them to form a trinomial, remember F.O.I.L. First Outer Inner Last.

So you multiply the first two numbers which is 9 and 9 so it's 81x^2

Then multiply the outer numbers 9 and 3 so you get 18x.
Then multiply the inner numbers and you get 72x.
Add the 18x and the 72x and you get 90x.

then multiply the last two numbers 8 and 3 and you get 24.

So it's: 81x^2+90x+24

Answer 4

I did not answer this too simple a question earlier as I thought many will answer it correctly, but I am surprised to find answerers knocked out by so simple a question.

Answer is 3(9x + 8)(3x + 1).

Answer 5

ok so...first of all...that is a binomial....and u cant factor this cuz its a prime...but u can foil it...which u just multiply
so its
81x^2+27x+72x+24
81x^2+99x+24....this is a trinomial.