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(5x + 4)(9x + 9)

2007-12-30 14:42:12 · 10 answers · asked by 11:11 3 in Science & Mathematics Mathematics

10 answers

Using the FOIL-ing method (multiplying first, outside, inside, last terms):

=(5x + 4)(9x + 9)
=45x² + 45x + 36x +36
=45x² + 81x + 36

2007-12-30 14:45:31 · answer #1 · answered by ¿ /\/ 馬 ? 7 · 0 0

use FOIL, first, outer,inner, last. You mulltiply the first two factors, 5x times 9x, then the outer, 5x times 9, inner two, 4 times 9x the last 4 times 9.The answer is
45x squared+ 45x + 36x +36 or
45x squared+81x +36
I hope that helps

2007-12-30 14:49:15 · answer #2 · answered by jessielynn 2 · 0 0

These are binomials.

FOIL it. First, outer, inner, last.

First being 5x x 9x, outer being 5x x 9, inner being 4 x 9x and last being 4 x 9.

This gives you 45x^2 (x squared), 45x, 36x, and 36.

Your overall answer will be these added together.

45x^2 + 81x + 36

2007-12-30 14:46:42 · answer #3 · answered by whoop! 4 · 1 0

umm..that is already factored..you want to solve it..i think..
to do that just double distribute:
(5x + 4)(9x + 9)
45x²+45x+36x+36
45x²+81x+36

hope this helped [=

2007-12-30 14:46:05 · answer #4 · answered by Mariee 4 · 0 0

well you can only simplify the 9x+9 which gives u 9(x+1)

which then gives u 9(5x+4)(x+1) hey buddy can you check my answers if im doing it right i know i am because this is all 2 years ago thanks :-)

2007-12-30 14:47:20 · answer #5 · answered by Anonymous · 0 0

45x^2 + 81x + 36

Ok, yes, I am a geek. I love Math. But hey, if you have a mind for math, go into Engineering...you will make great money, have job security, and be able to work anywhere in the world.

: )

2007-12-30 14:46:44 · answer #6 · answered by Muted Prophet 3 · 0 0

45x^2 + 45x +36x + 36 =

45x^2 + 81x + 36

2007-12-30 16:33:19 · answer #7 · answered by macks 3 · 0 0

45x^2 + 81x + 36

2007-12-30 14:45:49 · answer #8 · answered by coldinthecountry 2 · 0 0

45x² + 81x + 36

2007-12-30 15:18:39 · answer #9 · answered by vicky 2 · 0 0

9(x+1)(5x+4)

2007-12-30 14:46:17 · answer #10 · answered by Anonymous · 1 0

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