secant theta minus sintheta times tan theta
2007-12-30 14:09:55 · 5 answers · asked by Kelly S 1 in Science & Mathematics ➔ Mathematics
secx - sinxtanx
we know that tanx=sinx/cosx and secx= 1/cosx, so we get
=secx - sinxtanx
=(1/cosx) - sinx(sinx/cosx)
= 1-sin^2x/cosx (note: 1-sin^2x=cos^2x)
=cos^2x/cosx
=cosx
2007-12-30 14:13:43 · answer #1 · answered by ¿ /\/ 馬 ? 7 · 2⤊ 0⤋
secx - sinxtanx
= secx (1 - sin^2 x)
= cosx
2007-12-30 22:15:49 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋
secx - sinxtanx
= 1/cosx - sinx.sinx/cosx
= (1-sin^2x)/cosx
= cos^2x/cosx
= cosx
2007-12-30 22:14:03 · answer #3 · answered by mathnerd 2 · 0⤊ 0⤋
A tip: get everything to sines and cosines
1/cosx - sinx * (sinx/cosx)
(1-sin^2(x))/cosx
(cosx)^2 / cosx
cosx
2007-12-30 22:15:53 · answer #4 · answered by Anonymous · 0⤊ 0⤋
cos x.....
1/cos x - (sinx sinx)/cosx
(1 - sin^2 x)/ cos x
cos^2 x/ cos x = cos x
2007-12-31 01:55:51 · answer #5 · answered by muthu 2 · 0⤊ 0⤋