The radius of a sphere is given by the formula r= (0.75v)^1/3/ rr. where v is its volume. Find the radius of a spherical tank that has a volume of 32rr/3 cubic meters.
2007-12-30 13:18:24 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Hi,
V = 4/3πr³
32π/3 = 4/3r³
Multiply both sides by 3.
32π/3 = 4/3r³
3(32π/3) = 3(4/3r³)
32π = 4r³
Divide by 4.
32π.....4r³
------.=.----
..4.........4
8 = r³
So taking the cube root gives:
2 = r
So the radius = 2 meters
I hope that helps!! :-)
2007-12-30 13:23:50 · answer #1 · answered by Pi R Squared 7 · 1⤊ 5⤋
V = (4/3) Ï r ³
r ³ = 3V / 4Ï
r ³ = 32Ï / 4Ï
r ³ = 8
r = 2 m
2007-12-30 21:42:26 · answer #2 · answered by Como 7 · 0⤊ 0⤋
the radsius of a sphere is
cube root of ((3/4)(pi)(A))
the area is 4/3pi(r^3)
2007-12-30 13:35:50 · answer #3 · answered by Harris 6 · 1⤊ 0⤋
Is that "rr" supposed to be pi Ï ?? It looks bad, whatever it is.
Anyhow, r = cuberoot[ 0.75ÏV] where V is the volume, and Ï =3.14159.... Mercifully, it equals cube root of 8, which is 2.
Answer = 2.
2007-12-30 13:27:29 · answer #4 · answered by Charles M 6 · 0⤊ 3⤋
The formula should be r = (0.75v/Ï)^(1/3) = [3v/(4Ï)]^(1/3)
Plugging in v = 32Ï/3 gives:
r = [3(32Ï/3)/(4Ï)]^(1/3) = 8^(1/3) = 2
2007-12-30 13:31:22 · answer #5 · answered by a²+b²=c² 4 · 2⤊ 1⤋