2x^2 + 5x – 12
______________
9x^2 – 16
Divided By:
2x^2 – 7x + 6
______________
3x^2 – x – 4
2007-12-30 11:15:49 · 3 answers · asked by Abena 2 in Science & Mathematics ➔ Mathematics
Dividing fractions means multiply by the reciprocal
(2x^2+5x-12) /(9x^2-16) times (3x^2-x-4) /(2x^2-7x+6)
(2x-3)(x+4) (3x-4)(x+1)
----------------------------------- =
(3x-4)(3x+4) (2x-3)(x-2)
(2x-3)(3x-4)(x+4)(x+1)
------------------------------- =
(2x-3)(3x-4)(3x+4)(x-2)
(x+4)(x+1)
--------------
(3x+4)(x-2)
2007-12-30 11:36:43 · answer #1 · answered by Lady Lefty 3 · 1⤊ 0⤋
Let's start factorizing the four polynomials:
2x^2 + 5x – 12 = (x + 4)(2x - 3)
9x^2 – 16 = (3x - 4)(3x + 4)
2x^2 – 7x + 6 = (x - 2)(2x - 3)
3x^2 – x – 4 = (3x - 4)(x + 1)
Now we divide,
[ (x + 4)(2x - 3) ÷ (3x - 4)(3x + 4) ] / [ (x - 2)(2x - 3) ÷ (3x - 4)(x + 1) ]
= (x + 1)(x + 4) ÷ (x - 2)(3x + 4)
2007-12-30 19:35:15 · answer #2 · answered by fraukka 3 · 0⤊ 1⤋
=(2x-3)(x+4)/(3x+4)(3x-4) * (3x-4)(x+1)/(2x-3)(x-2)
=(x+4)(x+1)/(3x+4)(x-2)
2007-12-30 19:23:48 · answer #3 · answered by norman 7 · 0⤊ 0⤋