I am recently in an Algebra class and I am only okay at it. Would aomeone answer this question with all the steps please.
What is the sguare root of?
[ 144 x10 y12 z16]
2007-12-30 09:37:36 · 7 answers · asked by Crissiek 1 in Science & Mathematics ➔ Mathematics
(12) (x^5) (y^6) (z^8)
2007-12-30 10:05:15 · answer #1 · answered by Como 7 · 2⤊ 0⤋
Note that there are two solutions to a square root: â9 = ±3 since 3² = 9 and (-3)² = 9. Keeping that in mind, and rewriting 144 as 12²:
â(12² x¹⁰y¹²z¹⁶) = ±12x⁵y⁶z⁸
2007-12-30 09:50:08 · answer #2 · answered by Andy J 7 · 0⤊ 0⤋
You need to take the square root of each part seperately.
1 sqr of 144 is 12
2. sqr of x^10 is x^5 because you divide the original power (10) by the root number (2 in square root).
3. sqr of y^12 is y^6 - same principal as 2.
4. sqr of x^16 is z^8 - again, same principal as 2.
Put all answers together and you get 12 x^5 y^6 z^8
2007-12-30 09:49:10 · answer #3 · answered by Anonymous · 0⤊ 0⤋
well the square root of 144 is twelve..
but what is with the x10 y12 and z16 explain plz..
2007-12-30 09:42:41 · answer #4 · answered by Cherry 2 · 0⤊ 1⤋
the answer is 12 abs x^5 y^6 Z^8
2007-12-30 09:43:41 · answer #5 · answered by Anonymous · 0⤊ 2⤋
12 x^5 y^6 z^8
sqrt(x^m) = x^(m/2)
2007-12-30 09:43:15 · answer #6 · answered by norman 7 · 1⤊ 0⤋
square root of [144x^10y^12z^16] = ± 12 x^5y^6z^8
2007-12-30 09:47:09 · answer #7 · answered by sv 7 · 0⤊ 0⤋