Jaime and her friend can keyboard 45 words per minute. Six other students in the class can type 30 words per minute. Four students have not yet timed their speed. Find the ratio of students who have timed their keyboarding to those who have not.
.5
2
.7
1.5
2007-12-30 08:16:46 · 4 answers · asked by sunny p 1 in Science & Mathematics ➔ Mathematics
We know 8 people have had their keyboarding time recorded.
4 have not.
Since you want a ratio of the people already timed to the people not timed, we get 8:4 or 2:1 ratio [Answer: 2]
2007-12-30 08:21:58 · answer #1 · answered by ¿ /\/ 馬 ? 7 · 0⤊ 0⤋
Jaime and her friend = 2 people
Six other students = 6 people
2+6=8
That's people who have timed it.
4 students who have not timed themselved = 4 people
4=4
So the ratio is between those who have timed themselves and those who have not. So the ratio is 8:4, or 2:1 (which can be expressed simply as 2)
2007-12-30 16:30:36 · answer #2 · answered by kingof1337 2 · 0⤊ 0⤋
8 people already tried typing and 4 have not so then the ratio who timed it to not timed is 8:4 which is 2 because 8/4=2
2007-12-30 16:41:10 · answer #3 · answered by ViewtifulJoe 4 · 0⤊ 0⤋
You are just looking for ratios of students:
# who have timed their speed/# who have not = 8/4 = 2
Since Jamie and her friend constitute 2 people. Along with the other six, you have 8 who have timed their keyboarding
2007-12-30 16:24:58 · answer #4 · answered by duffy 4 · 0⤊ 0⤋