Prove this:
(tan A + sec A - 1) / (tan A + sec A + 1) = (1 + sin A) / cos A
2007-12-30 07:19:58 · 11 answers · asked by Chump 1 in Science & Mathematics ➔ Mathematics
It's not true. For instance when A = 0, the left hand side is 0 but the right hand side is 1.
2007-12-30 07:30:33 · answer #1 · answered by a²+b²=c² 4 · 0⤊ 0⤋
so your trying to get the left side the same as the right? i didnt think that if you had tan on the first side and sin and cos, then it wouldn't work because of different values, oh i dont know. Well, the fact that its + and - could mean that it cancels out, or not.
2007-12-30 07:30:54 · answer #2 · answered by Katy B 2 · 0⤊ 0⤋
Yah I am in trigonometry right now. And, I solved the left side by squaring both top and bottom and I got it as simple as sin²A.
2007-12-30 07:32:06 · answer #3 · answered by Math Wizard 3 · 0⤊ 0⤋
Hai Gowtham, don't be terrified of trigonometry. the sensation of the terror is extra risky. So, coaching extra issues on trigonometry.it will scientific care your impediment. there's no substitution for tough artwork. each and all the customary.
2016-11-26 21:29:07 · answer #4 · answered by ? 4 · 0⤊ 0⤋
I'm not sure about that question I'm in grade 10 and i just finished learning that stuff.... if that's out of a text book you could google the name of the book and search answers of the Internet
2007-12-30 07:24:10 · answer #5 · answered by Corwin C 2 · 0⤊ 2⤋
(tan A + sec A - 1) / (tan A + sec A + 1) = (1 + sin A) / cos A
Let's convert everything to sin/cos
(sinA/cosA + 1/cosA - 1) / (sinA/cosA + 1/cosA + 1) = (1 + sinA)/cosA
(sinA/cosA + 1/cosA - cosA/cosA) / (sinA/cosA + 1/cosA + cosA/cosA) = (1+sinA)/cosA
[(sinA +1 - cosA)/cosA] / [(sinA +1 +cosA)/cosA] = (1 +sinA)/cosA
(sinA + 1 - cosA)/(sinA +1 + cosA) = (1 + sinA)/cosA
(sinA + 1 - cosA)cosA = (1 + sinA)(1 + sinA + cosA)
sinAcosA + cosA - cos^2A = 1 + 2sinA + cosA +sinAcosA + sin^2A
- cos^2A = 1 + 2sinA + sin^2A
-cos^2A = (1 + sinA)^2
- cosA = - cosA
2007-12-30 07:45:28 · answer #6 · answered by Steve A 7 · 0⤊ 1⤋
holy crap!
That's like very hard. Try
purplemath.com and click on mathnerds.
They help with all math questions and they are online tutors.
Sorry, can't help you. I haven't learned that sh*t yet... :(
2007-12-30 07:31:19 · answer #7 · answered by Anonymous · 0⤊ 2⤋
Do you know how to do sin, cosine, and tangents?
If you do, then it should be simple!!
2007-12-30 07:23:01 · answer #8 · answered by Stay Beautiful 3 · 0⤊ 2⤋
go to askdoctormath.com its something like that.
2007-12-30 07:22:59 · answer #9 · answered by Pandachan 2 · 1⤊ 2⤋
i wish i could help... but i suck in math..
happy new year!!!!!!
2007-12-30 07:22:17 · answer #10 · answered by Anonymous · 0⤊ 2⤋