The problem is (2+3x)-6(x^2-x). The ^ indicates to the power of. Thanks a lot!
2007-12-30 07:12:23 · 5 answers · asked by Little Dreams 2 in Science & Mathematics ➔ Mathematics
PLEASE HELP ME!
2007-12-30 07:16:57 · update #1
(2+3x)-6(x^2-x)
2+3x -6x^2 +6x
2 +9x -6x^2
-6x^2 + 9x + 2
2007-12-30 07:18:40 · answer #1 · answered by Math Wizard 3 · 0⤊ 0⤋
It's simple:
(2+3x)-6(x^2-x) will become -6x^2+9x+2
You just multiply 6 with th braket and add them all up!
2007-12-30 16:26:40 · answer #2 · answered by ♫\\ Wanna Be Somebody // 3 · 0⤊ 0⤋
(2+3x)-6(x^2-x).
=2+3x -6x^2 +6x
= 2 +9x -6x^2
2007-12-30 15:16:38 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
solve what?
if you want to simplify, it is -6x^2+9x+2
2007-12-30 15:17:13 · answer #4 · answered by Adeel M 2 · 0⤊ 0⤋
(2+3x)-6(x^2+6x)
(2+3x)+(-6x^2+6x)
-6x^2+9x+2
2007-12-30 15:24:16 · answer #5 · answered by Anonymous · 0⤊ 0⤋