Chemistry Mole Problem: Who is right, me or my teacher?

Question

What mass will a sample of ammonium carbonate have if it contains 8.50 x 10^27 atoms?

My equation looked like this: (8.50x10^27 atoms)(1 mole/6.02x 10^23 atoms)(96.1g/1mol) but my answer is wrong apparently but maybe its teachers error?

But her (teacher) equation looked like

(8.50x10^27atoms)(1molec/14atoms)(1mole/6.02x10^23)(96.1g/1mole)

I asked a question previously and I got the answer that atoms and molescules are the same thing so is she right going abouts converting atoms to molecules.

Answer 1

your teacher is correct. 1mole is 6.02 x 10 ^ 23 molecules. But one molecule of (NH4)2CO3 has 14 atoms. Here you must count up the atoms in (NH4)2CO3.

Answer 2

You have the right idea in your approach but, your teacher threw you a curve ball by using 8.5 E 27 atoms instead of phrasing it as 8.5 E 27 molecules. Your approach is right for molecules but there are 14 atoms in the molecule for ammonium carbonate (NH4)2CO3. The teacher's equation accounts for this conversion. Try to think of a mole as an absolute number for anything.

Ex. a mole of oranges is 6.022 E 23

18 grams of water is a mole

Answer 3

1 molecule of (NH4)2CO3 contains 14 atoms (2 N, 8 H, 1 C and 3 O)

You must divide 8.50x10^27 atoms by 14 to get the number of molecules of (NH4)2CO3.

Your teacher is correct.

Answer 4

The first 4 letters of "mole" and "molecule" are the same thing for a reason.

Anyway, (NH4)2CO3 has a molar mass of 96.1 g/mole. You need to figure out how many moles you have, then multiply by g/mole and you have the mass.

By definition, the number of elementary entities (atoms, molecules, ions or other particles) in one mole of a substance, 6.02214199x10^23, is known as Avogadro's number.

Look at your units. You are given atoms, NOT molecules. Since the molecular formula of ammonium carbonate is (NH4)2CO3, you have 14 atoms per molecule.

So divide the number of atoms given by the number of atoms in each molecule, and you will know how many moles you have.
8.5x10^27 / 14 = 6.07x10^26 molecules of this stuff.
To get how many moles this is, use Avogadro:
6.07x10^26 molecules / 6.022x10^23molecules per mole = 1008 moles
Now we have moles, multiply by the mass/mole to get the mass:
1008 moles * 96.1 g/mole = 96.89 kg

Answer 5

8.5 x 10 exp 27 divided by 6.02 x 10 exp 23 will give you the number of moles. Then multiply it by the weight of one mole of (NH4)2CO3. N=7 H=1 C=12 O=8, so (2x7)+(8x1)+(1x12)+(3x8) = 58grams/mole Atoms and molecules are not the same. Molecules are made up of atoms. I don't know if I am right but crunch the numbers and see if it works.

Answer 6

You answered the question in terms of the mass of 8.50 x 10^27 molecules of (NH4)2CO3. Your teacher's calculation includes 14 atoms of all kinds in one "molecule" (NH4)2CO3. So teach is right.

Answer 7

ok. i admire chem. First we could observe some thing: 2 of those 3 questions take care of kilograms. we'd choose to handle grams. Convert in the previous persevering with. 2nd, the two steppers are not truly that undesirable. the 1st question needs the form of moles in 2kg of calcium carbonate. 2kg is 2000g. So, set up a share. (undergo in concepts. The mass of an ingredient is the mass of one unit and that i mole.) 2000g calcium carbonate over a million, accelerated by utilising a million mole of calcium carbonate divided by utilising what you go with to cancel (g). The mass of calcium carbonate is all the climate of the compound extra jointly. right here, that's a hundred.1g calcium carbonate. Now cancel your grams. After that, you're left with 2000 divided by utilising a hundred.a million that's 19.ninety 8. The unit you have left is moles, meaning there is nineteen.ninety 8 moles of calcium carbonate in a 2kg pattern. The third question is unquestionably an identical. the 2nd question i do no longer particularly understand myself. in case you have P4O10, why could you go with molecules of PO4? till it had broken down. then you definately could want greater innovations. i'm sorry i can not help with that one. For the record, questions a million and 3 are one steppers. they simply have a unit conversion. wish i replaced into of help.

Answer 8

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Answer 9

because he said it was E = MC SQ IS IT RIGHT or is it something else