2007-12-30 05:58:08 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Snarf's never going to grow a thumb at this rate.
2007-12-30 05:58:35 · update #1
Snarf, your going to have to do some non-euclidean geometry to make that one work. But you won't know the angles until you know the radius(es) of curvature.
If you can figure that out, you might grow some thumbs.
2007-12-30 07:14:30 · answer #1 · answered by Frst Grade Rocks! Ω 7 · 1⤊ 2⤋
Check your given. The lengths 3, 5, and 9 can not form a triangle. Well, 3 + 5 < 9. The sum of any two sides of a triangle must be greater than the third side.
teddy boy
2007-12-30 06:09:06 · answer #2 · answered by teddy boy 6 · 1⤊ 1⤋
Use trigonometrical functions to find out the angles. The side with the magnitude 9 is the hypotenuse. After that:
Sin A = x/h
Sin B = y/h
C = 90° (by visual observation of the magnitudes)
x=magnitud of a side
y=magnitud of the other side
h=hypotenuse
A, B, C = magnitude of the angles (must add up180°)
Also, many people think that this is an impossible triangle, they are wrong because of the formula:
y^2+x^2=z^2
Were x, y, z are magnitudes of the sides (Actually this is the most easier to sketch triangle)
2007-12-30 10:09:33 · answer #3 · answered by Rob 3 · 0⤊ 1⤋
You can't have a triangle where sum of lengths of 2 sides is less than the 3rd. Attach the 3 and 5 sides to the 9 side, and the two shorter sides don't reach each other.
2007-12-30 06:02:13 · answer #4 · answered by halac 4 · 3⤊ 1⤋
If A (xa ; ya) and B (xb ; yb), distance AB = sq. [ (xb -xa)² + (yb - ya)² ] <=> PQ = sq. [ (9 - 3)² + (5 - (- a million))² ] = sq. (36 + 36) = sq. (72) = 6 sq. (2) PR = sq. [ (6 - 3)² + (8 - (- a million))² ] = sq. (9 + 80 one) = sq. (ninety) = 3 sq. (10) QR = sq. [ (6 - 9)² + (8 - 5)² ] = sq. (9 + 9) = sq. (18) = 3 sq. (2) As PR is the longest facet, if PQR is rectangle, you need to have the relation : hypotenuse² = (leg a million)² + (leg 2)² PR² = PQ² + QR² ninety = 72 + 18 ===> ok. => PQR is a rectangle triangle.the terrific attitude is in Q (the letter that doesn't belong to the hypotenuse) *******
2016-11-26 21:10:27 · answer #5 · answered by rieck 4 · 0⤊ 0⤋
This is not possible..... the two smaller lenghts have to be equal to or greater than the longest side. 3 plus 5 is 8, which is LESS than 9, so it wont form a triangle.
hope that helps!
2007-12-30 06:37:37 · answer #6 · answered by Anonymous · 0⤊ 1⤋
I'd like to see you draw such a triangle, because it's impossible. 3 + 5 = 8. The other side is 9???
2007-12-30 06:09:53 · answer #7 · answered by Joe L 5 · 2⤊ 1⤋
there is no triangle here... the sum of the shortest two must exceed the largest...
which did not happen here...
so there are no angles...
§
2007-12-30 06:06:19 · answer #8 · answered by Alam Ko Iyan 7 · 1⤊ 0⤋
Yeah, what the first guy said. SOH CAH TOA. Sin Theta = opposite over hypotenuse. Punch in the numbers in a calculator and you can find the angles.
2007-12-30 06:03:34 · answer #9 · answered by Baby Esh 4 · 0⤊ 4⤋
There is no such triangle.
2007-12-30 06:12:17 · answer #10 · answered by Math Wizard 3 · 1⤊ 1⤋