2007-12-30 05:57:22 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Hi,
The angles are 90°, 36.87°, and 53.13°.
Because 3² + 4² = 5², this is a right triangle, so one angle is 90°.
When one leg is 3 and the hypotenuse is 5, then sin A = 3/5. So sin^-1(3/5) = 36.87°.
Using the leg of 4 and the hypotenuse is 5, then sin B = 4/5. So sin^-1(4/5) = 53.13°.
I hope that helps!! :-)
2007-12-30 06:15:00 · answer #1 · answered by Pi R Squared 7 · 2⤊ 0⤋
30, 60, 90
2007-12-30 14:06:13 · answer #2 · answered by Maharaja 4 · 0⤊ 0⤋
30, 60, 90
2007-12-30 14:04:27 · answer #3 · answered by Mike1942f 7 · 0⤊ 0⤋
37,53,90 using the Law of cosines.
a^2=b^2+c^2- 2bc cos(A)
a is the side opposite angle A
b--------------------------------B
c---------------------------------C
plug in the numbers and cos(A)=something
A= arccos(something)
Solve angles B and C the same way.
2007-12-30 14:22:40 · answer #4 · answered by cidyah 7 · 0⤊ 0⤋
30,60,90
2007-12-30 14:37:17 · answer #5 · answered by sparkle_disliker 3 · 0⤊ 0⤋