(20k^2 + 27k - 14) / (5k - 2)
2007-12-30 05:41:28 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Hi,
20k² + 27k - 14
----------------------- =
......5k - 2
(5k - 2)(4k + 7)
---------------------- = 4k + 7 <== ANSWER
......5k - 2
I hope that helps!! :-)
2007-12-30 05:46:51 · answer #1 · answered by Pi R Squared 7 · 0⤊ 2⤋
How we solve this one is all in the way we arrange the factors.
The denominator has a 5k, so at least ONE of the factors of the numerator MUST have a 5k as well, and that defines the factors of the numerator to be:
(5k + a)(4k + b)
Where a and b do like they did before:
4a + 5b = 27
ab = -14
We have to factor the -14 and see what comes up:
14 = 7 x 2
14 = 14 x 1
4(7) = 28
5(2) = 10
5(7) = 35
4(2) = 8
35 - 8 = 27
So, this means we make the 2 a -2 and make it a and 7 is b:
{(5k - 2)(4k + 7)}/(5k - 2)
You see that there is a 5k - 2 on both sides of the fraction, which mean they cancel out to give you:
4k + 7
And that's your answer.
2007-12-30 13:48:41 · answer #2 · answered by Eolian 4 · 0⤊ 0⤋
(5 k - 2)(4k + 7) / (5k - 2)
4k + 7
2007-12-31 05:34:34 · answer #3 · answered by Como 7 · 1⤊ 0⤋
i got (155k^2-14)/ -2 which equals to 155k^2+7
2007-12-30 13:53:22 · answer #4 · answered by cool_chick 2 · 0⤊ 0⤋