(40x^5y^6z^3) / (8x^3y^4z)?

Question

How do I solve this?

And what grade level math is this?

Answer 1

take it apart:

40/8 = 5

x^5 / x^3 = x^2

y^6 / y^4 = y^2

z^3 / z = z^2

final ans. = 5 x^2 y^2 z^2

This could easily be algebra I.

that's it! :)

Answer 2

Hi,

To simplify a fraction like this, divide or reduce the coefficients. Then subtract the top exponent of a variable minus the bottom exponent of the variable. That answer is currently in the numerator. If any variable has a negative exponent, it must move into the denominator. This changes the exponent to a positive number.

40x^5y^6z^3
----------------- = 5x²y²z² <== ANSWER
8x^3y^4z

I hope that helps!! :-)

Answer 3

the answer's 5x^2y^2z^2

you divide 40x^5 by 8x^3 which equals 5x^2
you subtract the exponents
y^6/y^4=y^2
z^3/z^1=z^2

Answer 4

(40x^5y^6z^3) / (8x^3y^4z)
Write this as
(40)(xxxxx)(yyyyyy)(zzz) / (8)(xxx)(yyyy)(z)
=5(xx)(yy)(zz)
=5x^2y^2z^2
There are short-cuts, but all are based on the concept
that I've shown here.
This is, I would guess, Grade 9 math.

Answer 5

(40x^5y^6z^3) / (8x^3y^4z) = 5x²y²z²
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Answer 6

40x^5 y^6 z^3
------------------
8x^3y^4 z

5x^2 y^2 z^2