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1) inverse sin 3x
or
2) inverse sin (3x)

For number (1) without brackets around the answer is apparantely from the markscheme 3/(Squareroot(1-9x^2))
For number (2) with the brackets around 3x the answer is apparantely -24/(squareroot(1-9x^2)

I got the first answer for both of them. I'm assuming the mark scheme is right? Please help!

2007-12-30 01:52:53 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

It sounds like in both of them you are looking at the number whose sin is 3x. In that case, they're the same function. (And the possibility of safely adding a constant multiple of 2 pi doesn't change the derivative any.)

Anyhow, arcsin is an increasing function when x is a small positive number, so the derivative shouldn't be a function that is negative in that range.

2007-12-30 11:17:17 · answer #1 · answered by Curt Monash 7 · 0 0

no way you can have -24/(squareroot(1-9x^2)

they were the same answer 3/(Squareroot(1-9x^2))

because they are the same question.

2007-12-30 12:17:18 · answer #2 · answered by Helper 6 · 0 0

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