are the lines y=x-4 and y= -x+4 perpendicular or parallel or neither?

Answer 1

m1 = 1
m2 = - 1
m1 x m2 = - 1
Lines are perpendicular.

Answer 2

Perpendicular. Their slopes are exact opposites. The +4 and -4 don't actually matter and they're only included to trip you up. The only thing that matters is the coefficient of X, which is 1 in the first, and -1 in the second.

Answer 3

to verify, place the two equations in y = mx + b form. 7x - 4y = 4 provides (7/4)(x) + -a million x-4y=3 provides (a million/4)(x) - 3 = y Parallel strains have an identical slope. Perpendicular strains have slopes that are unfavorable reciprocals. the slopes indexed right here are 7/4 and a million/4, so the respond is neither.

Answer 4

They are perpendicular. When the slopes of the lines are negative reciprocals of each other, they must be perpendicular. So, in this case +1 and -1 are the slopes. They are negative reciprocals of each other so the lines are in fact perpendicular.

Answer 5

Yes, they are perpendicular::

m (slope of one line) = negative reciprocal of another line

y = x -4 ; m = 1

y = -x + 4; m = -1 ( so it is the negative reciprocal of 1)

Answer 6

one=1

Answer 7

As mentioned above, the given lines are perpendicular....

Answer 8

perpendicular since the products of their slope is -1

Answer 9

They are perpendicular. When the slope of a line is a negative reciprocal of the slope of another line, then the lines are perpendicular. If you graph both lines, you can tell.

Why did I get thumbs down for this? I didn't just make this stuff up, graph a couple lines and see for yourself. When you multiply a number by its negative reciprocal you will get -1.

Answer 10

perpendicular
as the equation can be writen as y=mx + c
it is perpendicular if the first "m" and the second "m" mulitply to equal -1
ie. m1 x m2 = -1
-1 x 1 = -1
therefore they are perpendicular