2007-12-29 23:45:30 · 4 answers · asked by kezz 1 in Science & Mathematics ➔ Mathematics
m = 5
y - 9 = 5(x - 1)
y = 5x - 5 + 9
y = 5x + 4
2007-12-30 00:15:22 · answer #1 · answered by Como 7 · 1⤊ 0⤋
The given line is y = -1/5 x
so it is in the slope intercept form (y =mx + b)
m = -1/5 ; b =0
for perpendicular to the given line:
m = -1/ (-1/5) = 5
Substitute the give point in the equation of the perpendicular line
y = 5x + b
9 = 5(1) + b ; b = 4
y = 5x + 4 ----------answer
2007-12-30 07:58:54 · answer #2 · answered by Synchronizers 3 · 0⤊ 0⤋
Line is perpendicular gradient of line = 5
Equation of line = y -y1 =m(x-x1)
m = 5
y1 = 9
x1=1
y-9=5(x-1)
y-9=5x-5
y=5x+4
2007-12-30 07:58:53 · answer #3 · answered by Murtaza 6 · 0⤊ 0⤋
y=5x+b
substitute(1,9)
9=5+b
b=4
y=5x+4
2007-12-30 08:05:37 · answer #4 · answered by someone else 7 · 0⤊ 0⤋